Factorize

i.) $5 p^{2} - 25 p + 20$

ii.) $x^{2} + 11 x + 28$

Open in App

Solution

$i) 5 p^{2} - 25 p + 20$

$= 5 (p^{2} - 5 p + 4)$

$= 5 (p^{2} - 4 p - p + 4)$

$= 5 (p - 1) (p - 4)$

$i i) x^{2} + 11 x + 28$

$= x^{2} + 7 x + 4 x + 28$

$= (x + 7) (x + 4)$

Suggest Corrections

Similar questions

(5 p^{2} - 25 p + 20) \div (p - 1)

(5 p^{2} - 25 p + 20) \div (p - 1)

(5 p^{2} - 25 p + 20) \div (p - 1)

8 p^{3} + \frac{12}{5} p^{2} + \frac{6}{25} p + \frac{1}{125}

\frac{x^{2} + 11 x + 24}{x^{2} - 15 x + 56} \div \frac{x^{2} - x - 12}{x^{2} - 11 x + 28} .

Join BYJU'S Learning Program