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Byju's Answer
Standard IX
Mathematics
Taking Out Common Factors
Factorize 4...
Question
Factorize
(
4
x
−
1
5
)
2
−
(
x
+
1
2
)
2
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Solution
(
4
x
−
1
5
)
2
−
(
x
+
1
2
)
2
=
(
4
x
−
1
5
+
x
+
1
2
)
(
4
x
−
1
5
−
x
−
1
2
)
=
(
5
x
+
1
2
−
1
5
)
(
3
x
−
1
5
−
1
2
)
=
(
5
x
+
5
−
2
10
)
(
3
x
+
−
2
−
5
10
)
=
(
5
x
+
3
10
)
(
3
x
−
7
10
)
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