Factorize:
px − 5q + pq − 5x

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Solution

We have:
$p x - 5 q + p q - 5 x = (p x - 5 x) + (p q - 5 q)$
$= x (p - 5) + q (p - 5) = (p - 5) (x + q)$

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(9 p - 5 q)^{2} + 180 p q = (9 p + 5 q)^{2}

Question 5(ii)
Show that:
$(9 p - 5 q)^{2} + 180 p q = (9 p + 5 q)^{2}$

(9 p - 5 q)^{2} + 180 p q

3 p^{2} = 5 p + 2

3 q^{2} = 5 q + 2

p \neq q

p q

p^{2} + 25 q^{2} = 634

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