Factorize √3 x2 + 5x + 2√3 = 0 by splitting the middle term and find the value of x.
x=−2√3,x=−√3
Multiply √3 with 2√3 and we get 6.
Factors of 6 are,
1×6 = 6 sum 1+ 6 = 7
2×3= 6 sum 2+ 3 = 5
So our required pair of factors is 2 and 3.
⇒√3x2+5x+2√3=0
⇒√3x2+3x+2x+2√3=0
⇒√3x (x+√3)+2 (x+√3)=0
⇒(√3x+2) (x+√3)=0
∴ Factors are (√3x+2),(x+√3)
⇒(√3x+2)=0 or (x+√3)=0
⇒x=−2√3 or x=−√3