Question

Factorize $\sqrt{3}$ $x^2$ + 5x + 2$\sqrt{3}$ = 0 into the form (ax+b)(cx+d)=0.

• A. ($\sqrt{3}$x + 2) (x - $\sqrt{3}$) = 0
• B. ($\sqrt{3}$x + 2) (x + $\sqrt{3}$) = 0
• C. ($\sqrt{3}$x - 2) (x + $\sqrt{3}$) = 0
• D. ($\sqrt{3}$x - 2) (x - $\sqrt{3}$) = 0

Answer 1

The correct option is B

($\sqrt{3}$x + 2) (x + $\sqrt{3}$) = 0

Multiply $\sqrt{3}$ with 2$\sqrt{3}$ and we get 6

Pairs of 6 are

1$\times$6 = 6 sum 1+ 6 = 7

2$\times$3= 6 sum 2+ 3 = 5

So our required pair is 2 and 3

$\Rightarrow$ $\sqrt{3}$ $x^2$ + 5x + 2$\sqrt{3}$ = 0

$\Rightarrow$ $\sqrt{3}$ $x^2$ + 3x + 2x +2$\sqrt{3}$ = 0

$\Rightarrow$$\sqrt{3}$x(x+$\sqrt{3}$ )+ 2(x+$\sqrt{3}$ )= 0

$\Rightarrow$ ($\sqrt{3}$x + 2) (x + $\sqrt{3}$) = 0