Factorize -5 x2 - 8x - 3-5 - 0 into the form -5 x2 - px - qx -3-5 - 0-Find the value of p and q-

Multiply √(5) with 3√(5) and we get 15 Pairs of 15 are 1×15 = 15 sum 1+ 15 = 16 5×3= 15 sum 5 + 3 = 8 So our required pair is 5 and 3 √( ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard X

Mathematics

Solving a Quadratic Equation by Factorization Method

Factorize √5 ...

Question

Factorize $\sqrt{5}$ $x^{2}$ + 8x + 3 $\sqrt{5}$ = 0 into the form $\sqrt{5}$ $x^{2}$ + px + qx +3 $\sqrt{5}$ = 0.Find the value of p and q.

Open in App

Solution

Multiply $\sqrt{5}$ with 3 $\sqrt{5}$ and we get 15

Pairs of 15 are

1 $\times$ 15 = 15 sum 1+ 15 = 16

5 $\times$ 3= 15 sum 5 + 3 = 8

So our required pair is 5 and 3

$\sqrt{5}$ $x^{2}$ + 8x + 3 $\sqrt{5}$ = 0

$\sqrt{5}$ $x^{2}$ + 5x + 3x +3 $\sqrt{5}$ = 0

So, p = 5 and q = 3.

Suggest Corrections

Similar questions

Factorize $\sqrt{5} x^{2} + 8 x + 3 \sqrt{5} = 0$ into the form $\sqrt{5} x^{2} + p x + q x + 3 \sqrt{5} = 0$ . What is the value of $p^{2} + q^{2}$ ?

Write $x^{2}$ +8x+16 =0 in the form $x^{2}$ +px+qx+16 =0 such that p x q = 16

Nikhil expressed the quadratic equation $x^{2} + 10 x + 16 = 0$ in the form $x^{2} + p x + q x + 16 = 0$ such that the product of $p$ and $q$ is $16.$ Choose the correct values of $p$ and $q .$

Q. If p and

q (\neq 0)

are the roots of the equation

x^{2} + p x + q = 0,

then the least value of

x^{2} + p x + q (x ϵ R)

is:

Write $x^{2}$ +10x+16 =0 in the form $x^{2}$ +px+qx+16 =0 such that p x q = 16

Join BYJU'S Learning Program

Factorize √5 x2 + 8x + 3√5 = 0 into the form √5 x2 + px + qx +3√5 = 0.Find the value of p and q.

Multiply √5 with 3√5 and we get 15 Pairs of 15 are 1×15 = 15 sum 1+ 15 = 16 5×3= 15 sum 5 + 3 = 8 So our required pair is 5 and 3 √5 x2 + 8x + 3√5 = 0 √5 x2 + 5x + 3x +3√5 = 0 So, p = 5 and q = 3.​

Factorize $\sqrt{5}$ $x^{2}$ + 8x + 3 $\sqrt{5}$ = 0 into the form $\sqrt{5}$ $x^{2}$ + px + qx +3 $\sqrt{5}$ = 0.Find the value of p and q.

Multiply $\sqrt{5}$ with 3 $\sqrt{5}$ and we get 15

Pairs of 15 are

1 $\times$ 15 = 15 sum 1+ 15 = 16

5 $\times$ 3= 15 sum 5 + 3 = 8

So our required pair is 5 and 3

$\sqrt{5}$ $x^{2}$ + 8x + 3 $\sqrt{5}$ = 0

$\sqrt{5}$ $x^{2}$ + 5x + 3x +3 $\sqrt{5}$ = 0

So, p = 5 and q = 3.