Question

Factorize the below equation:

$3-a(4+7a)$

• A. $\left(7a\right)(1+a)$
• B. $(3-7a)(1+a)$
• C. $(3+7a)(1-a)$
• D. $\left(7a\right)\left(a\right)$

Answer 1

The correct option is B $(3-7a)(1+a)$

$3-a(4+7a)$
$=-7a^2-4a+3$
$=-7a^2-7a+3a+3$
$=-7a(a+1)+3(a+1)$
$=(a+1)(3-7a)$