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Question

Factorize the equation 4a2−49b2+2a−7b

A
(2a7b)(a+7b+1)
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B
(2a7b)(2a+7b+1)
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C
(a7b)(2a+7b+3)
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D
(2ab)(2a+7b+13)
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Solution

The correct option is C (2a7b)(2a+7b+1)
4a249b2+2a7b
=(2a)2(7b)2+2a7b
=(2a+7b)(2a7b)+(2a7b)
=(2a7b)(2a+7b+1)

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