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Question

Factorize the equation 4x212axy2z22yz+9a2

A
(2x3a+y)(2x3ayz)
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B
(2x3a+y+z)(2x3ayz)
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C
(3a+y+z)(2x3ayz)
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D
(2x3a+yz)(2xayz)
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Solution

The correct option is B (2x3a+y+z)(2x3ayz)
4x212axy2z22yz+9a2
=(4x212xa+9a2)(y2+2yz+z2)
=[(2x)(2×2x×3a)+(3a)2][(y)2+2yz+(z)2]
=(2x3a)2(y+z)2
Using,
a2b2=(a+b)(ab)
=(2x3a+y+z)(2x3ayz)

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