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Question

Factorize the equation 9a2+3a−8b−64b2

A
(3a8b)(3a+8b+3)
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B
(a8b)(3a+b+1)
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C
(3a8b)(3a+8b+1)
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D
(3ab)(a+8b+1)
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Solution

The correct option is C (3a8b)(3a+8b+1)
9a2+3a8b64b2
=9a264b2+3a8b
=(3a+8b)(3a8b)+3a8b
=(3a8b)(3a+8b+1)

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