Factorize the equation: x3-3x2-9x-5.
Step 1: Split the middle terms
Let f(x)=x3-3x2-9x-5
f(x)=x3+x2-4x2-4x-5x-5f(x)=x2(x+1)-4x(x+1)-5(x+1)f(x)=(x+1)(x2-4x-5)
Step 2: Factorize the quadratic equation
f(x)=(x+1)(x2-5x+x-5)f(x)=(x+1)x(x-5)+1(x-5)f(x)=(x+1)(x-5)(x+1)
Hence, the factorized form of the polynomial x3-3x2-9x-5 is (x+1)(x+1)x-5.
Solve: x3−3x2−9x−5