Factorize the following
$10 - 7 x - 3 x^{2}$

(1 - x) (3 x + 10)

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(1 + x) (3 x + 10)

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(1 - x) (3 x - 10)

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None of these

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Solution

The correct option is A $(1 - x) (3 x + 10)$
$10 - 7 x - 3 x^{2}$

$10 + - 3 = 7$ ...............the split for the middle term

$10 \times - 3 = - 30$ .............the product of the coefficient of the first and last term
Now splitting the middle term, we get

$- (3 x^{2} + 7 x - 10)$

$= - (3 x^{2} + 10 x - 3 x - 10)$

$= - (3 x (x - 1) + 10 (x - 1))$

$= - (3 x + 10) (x - 1)$

$= (3 x + 10) (1 - x)$

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Similar questions

∣ ∣ ∣ ∣ ∣ ∣ \begin{matrix} 1 + x & 2 & 3 & 4 1 & 2 + x & 3 & 4 1 & 2 & 3 + x & 4 1 & 2 & 3 & 4 + x \end{matrix} ∣ ∣ ∣ ∣ ∣ ∣

= x^{3} (x + 10)

f (x) = {tan}^{- 1} (\frac{3 - x^{3}}{x + 3 x^{2}}),

f^{'} (- 1)

\frac{x^{2} (x - 1)}{x^{3} (x + 1)}

x (3 x - 11) + 6

l i m x \to 0 \frac{1 - c o s 3 x}{x (3^{x} - 1)} =

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