Factorize the following:
$20 q p^{2} + 10 p q$

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Solution

$(20 p^{2}) * q + 10 p q$
Take 10pq out of each term as it is common to both.
$10 p q \times (2 p + 1)$
Thus $(20 p^{2}) \times q + 10 p q$ can be factorised to $10 p q \times (2 p + 1)$

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