Question

Factorize the following :

$2a^4{b}^4-3a^3{b}^5+4a^2{b}^5$

Answer 1

$2a^4{b}^4-3a^3{b}^5+4a^2{b}^5$

HCF of 2, 3, 4 = 1

HCF of $a^4,a^3,a^2=a^2$

HCF of $b^4,b^5,b^5=b^4$

$\therefore 2a^4{b}^4-3a^3{b}^5+4a^2{b}^5=a^2{b}^4$

$2a^2-3ab+4b$