Factorize the following
$3 x^{2} + 19 x + 6$

(3 x + 1) (x + 6)

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

(3 x - 1) (x + 6)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

(3 x + 1) (x - 6)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

None of these

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $(3 x + 1) (x + 6)$
Given,
$3 x^{2} + 19 x + 6$

$18 \times 1 = 18$ .............splitting the last term

$18 + 1 = 19$ ........................splitting the middle term
Now, splitting the middle term

$3 x^{2} + 18 x + x + 6$

$3 x (x + 6) + 1 (x + 6)$

$(x + 6) (3 x + 1)$

Suggest Corrections

Similar questions

(x + 1) (x + 2) (x + 3) (x + 6) = 3 x^{2},

Factorise $x^{2} - 3 x + 2$ by using the Factor Theorem.

x^{2} - 3 x + 6

\frac{1}{x}

f : x \to 3 x + 6

h : x \to \frac{x}{3}

(f^{- 1} o h^{- 1}) (x) = (h o f)^{- 1} (x)

Join BYJU'S Learning Program