Factorize the following
$6 x^{2} - 5 x + 1$

(3 x - 1) (2 x - 1)

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(3 x + 1) (2 x - 1)

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(3 x - 1) (2 x + 1)

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None of these

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Solution

The correct option is A $(3 x - 1) (2 x - 1)$
$6 x^{2} - 5 x + 1$

$- 3 + - 2 = - 5$ .............the split for the middle term
$- 3 \times - 2 = 6$ ..............the product of the coefficient of the first and last term

Now splitting the middle term, we get

$= 6 x^{2} - 3 x - 2 x + 1$
$= 3 x (2 x - 1) - 1 (2 x - 1)$

$= (2 x - 1) (3 x - 1)$

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