Question

Factorize the following algebraic expression: $a^2-14a-51$

Answer 1

Given :$a^2-14a-51$
On splitting the middle term , we get
$a^2+3a-17a-51$
$=a(a+3)-17(a+3)$
$=(a-17)(a+3)$

Hence, $a^2-14a-51=(a-17)(a+3)$