Factorize the following equation by the grouping method
$1 - 2 a - 3 a^{2}$

(1 - 3 a) (1 + a)

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(a) (a + 1)

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(a - 1) (a)

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(1 - a) (a - 1)

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Solution

The correct option is A $(1 - 3 a) (1 + a)$
$1 - 2 a - 3 a^{2}$
$= - 3 a^{2} - 2 a + 1$
$= - 3 a^{2} - 3 a + 1 a + 1$
$= - 3 a (a + 1) + 1 (a + 1)$
$= (a + 1) (1 - 3 a)$

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