Factorize the following equation by the grouping method
$a b - 2 b + a^{2} - 2 a$

(a - 2) (a + b)

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(a + 2) (2 a + b)

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(a + 2) (a - b)

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(a + 2) (a - 2 b)

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Solution

The correct option is A $(a - 2) (a + b)$
$a b - 2 b + a^{2} - 2 a$
$= b (a - 2) + a (a - 2)$
$= (a - 2) (a + b)$

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Similar questions

a b - 2 b + a^{2} - 2 a

(a + 2 b) x + (2 a - b) y = 2

(a - 2 b) x + (2 a + b) y = 3

(a + 2 b) x + (2 a - b) y = 2

(a - 2 b) x + (2 a + b) y = 3

(a + b)^{2} + (a - b)^{2}

2 a + 2 b

2 a - 2 b

2 a^{2} + 2 b^{2}

2 a^{2} + 2 b^{2}

(a + 2 b) x + (2 a - b) y = 2, (a - 2 b) x + (2 a + b) y = 3

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