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Question

Factorize the following equation by the grouping method
x(6x−5y)−4(6x−5y)2

A
(3x5y)(20y23x)
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B
(6x5y)(20y23x)
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C
(xy)(10y17x)
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D
(x5y)(10y17x)
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Solution

The correct option is B (6x5y)(20y23x)
x(6x5y)4(6x5y)2
=x(6x5y)4(6x5y)(6x5y)
=(6x5y)[x4(6x5y)]
=(6x5y)(x24x+20y)
=(6x5y)(20y23x)

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