Factorize the following expression:
x3-x2+ax+x-a-1
Factorizing the given expression:
x3-x2+ax+x-a-1=x3-x2+ax-a+x-1(Rearrangingtheterms)=x2(x-1)+a(x-1)+(x-1)=(x-1)(x2+a+1)(Takingx-1common)
Hence, after factorizing we get x3-x2+ax+x-a-1=(x-1)(x2+a+1).
(x+1) is a factor of the polynomial (a) x3+x2−x+1 (b) x3+2x2−x−2 (c) x3+2x2−x+2 (d) x4+x3+x2+1
Simplify the following algebraic expressions. x2+a2ab+x−aax−x3b
Determine which of the following polynomials have (x+1) as a factor: [2 MARKS] (i) x3+x2+x+1 (ii) x4+x3+x2+x+1