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Question

Factorize the following expression
xy−xz+ay−az

A
(yz)(x+a)
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B
(y+z)(x+a)
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C
(yz)(xa)
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D
None of these
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Solution

The correct option is A (yz)(x+a)
xyxz+ayaz

x common | a common

=x(yz)+a(yz)

Taking (yz) as common

=(yz)(x+a)

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