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Byju's Answer
Standard VIII
Mathematics
Factorisation by Common Factors
Factorize the...
Question
Factorize the following expressions:
2
a
5
b
3
−
14
a
2
b
2
+
4
a
3
b
Open in App
Solution
Let us first find the HCF of all the terms of the given polynomial
2
a
5
b
3
−
14
a
2
b
2
+
4
a
3
b
by factoring the terms as follows:
2
a
5
b
3
=
2
×
a
×
a
×
a
×
a
×
a
×
b
×
b
×
b
14
a
2
b
2
=
2
×
7
×
a
×
a
×
b
×
b
4
a
3
b
=
2
×
2
×
a
×
a
×
a
×
b
Therefore,
H
C
F
=
2
×
a
×
a
×
b
=
2
a
2
b
Now, we factor out the HCF from each term of the polynomial
2
a
5
b
3
−
14
a
2
b
2
+
4
a
3
b
as shown below:
2
a
5
b
3
−
14
a
2
b
2
+
4
a
3
b
=
2
a
2
b
(
a
3
b
2
−
7
b
+
2
a
)
Hence,
2
a
5
b
3
−
14
a
2
b
2
+
4
a
3
b
=
2
a
2
b
(
a
3
b
2
−
7
b
+
2
a
)
.
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