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Question

Factorize the following expressions:
2a5b314a2b2+4a3b

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Solution

Let us first find the HCF of all the terms of the given polynomial 2a5b314a2b2+4a3b by factoring the terms as follows:

2a5b3=2×a×a×a×a×a×b×b×b14a2b2=2×7×a×a×b×b4a3b=2×2×a×a×a×b

Therefore, HCF=2×a×a×b=2a2b

Now, we factor out the HCF from each term of the polynomial 2a5b314a2b2+4a3b as shown below:

2a5b314a2b2+4a3b=2a2b(a3b27b+2a)

Hence, 2a5b314a2b2+4a3b=2a2b(a3b27b+2a).

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