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Question

Factorize the following expressions :
(i) (5x1x)2+4(5x1x)+4,x0

(ii) 36x212x+125y2

(iii) x4+x2+1

(3 marks)


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Solution

(i) (5x1x)2+4(5x1x)+4

=(5x1x)2+2×(5x1x)×2+22

=(5x1x+2)2 (1 mark)

(ii) 36x212x+125y2

=(6x)22×6x×1+12(5y)2

=(6x1)2(5y)2

={(6x1)5y}{(6x1)+5y}

=(6x15y)(6x1+5y)

=(6x5y1)(6x+5y1) (1 mark)

(iii) x4+x2+1=(x4+2x2+1)x2

=(x2+1)2x2=(x2+1x)(x2+1+x)

=(x2x+1)(x2+x+1) (1 mark)

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