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Question

Factorize the following using the Identities:
x210x+25

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Solution

x210x+25
Comparing x210x+25 with a22ab+b2, we see that a=x,b=5.
Now, x210x+25=x22(x)(5)+52
Using, a22ab+b2=(ab)2,a=x and b=5,
we get x210x+25=(x5)2
The factors of x210x+25 are (x5) and (x5)

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