Factorize the following using the Identities: x2−10x+25
Open in App
Solution
x2−10x+25 Comparing x2−10x+25 with a2−2ab+b2, we see that a=x,b=5. Now, x2−10x+25=x2−2(x)(5)+52 Using, a2−2ab+b2=(a−b)2,a=x and b=5, we get x2−10x+25=(x−5)2 ∴ The factors of x2−10x+25 are (x−5) and (x−5)