CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Factorize the following using the Identities:
x210x+25

Open in App
Solution

x210x+25
Comparing x210x+25 with a22ab+b2, we see that a=x,b=5.
Now, x210x+25=x22(x)(5)+52
Using, a22ab+b2=(ab)2,a=x and b=5,
we get x210x+25=(x5)2
The factors of x210x+25 are (x5) and (x5)

flag
Suggest Corrections
thumbs-up
1
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Method of Identities
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon