wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Factorize the following
x2+14x−15

A
(x1)(x+15)
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
(x+1)(x+15)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
(x1)(x15)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
None of these
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A (x1)(x+15)
In the given polynomial x2+14x15,

The first term is x2 and its coefficient is 1.

The middle term is 14x and its coefficient is 14.

The last term is a constant term 15.

Multiply the coefficient of the first term by the constant 1×(15)=15.

We now find the factor of 15 whose sum equals the coefficient of the middle term, which is 14 and then factorize the polynomial x2+14x15 as shown below:
x2+14x15

=x2+15xx15

=x(x+15)1(x+15)

=(x1)(x+15)

Hence, x2+14x15=(x1)(x+15).

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Method of Common Factors
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon