Factorize the following: ${(x + 4 y)}^{2} - 16 x y$

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Solution

Simplifying ${(x + 4 y)}^{2} - 16 x y$

${(x + 4 y)}^{2} - 16 x y$

$= x^{2} + 16 y^{2} + 8 x y - 16 x y$

$= x^{2} + 16 y^{2} - 8 x y$

$= {(x - 4 y)}^{2}$

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Similar questions

16 x^{2} + 4 y^{2} + 9 z^{2} + 16 x y + 12 y z + 24 x z

Factorize:

$16 x^{2} + 4 y^{2} + 9 z^{2} - 16 x y - 12 y z + 24 x z$

Factrorise
$16 x^{2} + 4 y^{2} + 9 z^{2} - 16 x y - 12 y z + 24 x z$

$(a x + b y)^{2} = (a x)^{2} + 16 x y + 4 (y)^{2}$ , then $(a + b)^{2}$ is equal to

Question 29
Factorise the following:

9 x^{2} + 4 y^{2} + 16 z^{2} + 12 x y - 16 y z - 24 x z

25 x^{2} + 16 y^{2} + 4 z^{2} - 40 x y + 16 y z - 20 x z

16 x^{2} + 4 y^{2} + 9 z^{2} - 16 x y - 12 y z + 24 x z

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