Factorize the given equation by grouping method $(2 a - b)^{2} - 10 a + 5 b$

(2 a + b) (2 a - b - 5)

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(2 a - b) (2 a + b - 5)

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(2 a - b) (2 a - b - 5)

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(2 a - b) (2 a - b + 5)

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Solution

The correct option is C $(2 a - b) (2 a - b - 5)$
$(2 a - b)^{2} - 10 a + 5 b$
$= (2 a - b)^{2} - 5 (2 a - b)$
$= (2 a - b) (2 a - b - 5)$

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