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Question

Factorize the given expressions:

i.)4a2+4ab4ca

ii.)x2yz+xy2z+xyz2

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Solution

Factorisation:

(i) 4a2=2×2×a×a

4ab=2×2×a×b

4ca=2×2×c×a

therefore4a2+4ab4ca=(2×2×a×a)+(2×2×a×b)(2×2×c×a)

=2×2×a[(a)+bc]

=4a(a+bc)


(ii) x2yz=x×x×y×z

xy2z=x×y×y×z

xyz2=x×y×z×z

x2yz+xy2z+xyz2=(x×x×y×z)+(x×y×y×z)+(x×y×z×z)

=x×y×z[x+y+z]

=xyz(x+y+z)


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