Factorize the given expressions:
(i) −4a2+4ab−4ca
(ii) x2yz+xy2z+xyz2
Factorisation:
(i) 4a2=2×2×a×a
4ab=2×2×a×b
4ca=2×2×c×a
∴−4a2+4ab−4ca=−(2×2×a×a)+(2×2×a×b)−(2×2×c×a)
=2×2×a[−(a)+b−c]
=4a(−a+b−c)
(ii) x2yz=x×x×y×z
xy2z=x×y×y×z
xyz2=x×y×z×z
∴x2yz+xy2z+xyz2=(x×x×y×z)+(x×y×y×z)+(x×y×z×z)
=x×y×z[x+y+z]
=xyz(x+y+z)