Factorize using appropriate identities.
$4 y^{2} - 4 y + 1$

Open in App

Solution

We know $4 y^{2} - 2 y + 1$ $= (2 y)^{2} - 2 (2 y) (1) + (1)^{2}$
We know appropriate identities $x^{2} - 2 x y + y^{2} = (x - y)^{2}$
Here $x = 2 y$ and $y = 1$ , then
$4 y^{2} - 4 y + 1 =$ $(2 y - 1)^{2}$

Suggest Corrections

Similar questions

9 x^{2} + 6 x y + y^{2}

4 y^{2} - 4 y + 1

x^{2} - \frac{y^{2}}{100}

4 y^{2} - 4 y + 1

t^{2} - 2 t + 1

Factorise the following using appropriate identities: [4 MARKS]
$1) 9 x^{2} + 6 x y + y^{2}$
$2) 4 y^{2} - 4 y + 1$

16 x^{2} + 24 x y + 9 y^{2}

Join BYJU'S Learning Program