Factorize using Identity- 27 x3-135 x2-225 x-125Pls- Can u help me in this problem

27x³ 135x² 225x 125 =(3x)³ + ( 5)³ + 3(3x)×(5)× (3x 5)× (3x 5)³ ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard IX

Mathematics

Identity (x+y)(x-y)

Factorize usi...

Question

Factorize using Identity 27x³-135x²-225x-125.

Open in App

Solution

Given expression: 27x³-135x²-225x-125=(3x)³ + (-5)³ - 3(3x)×(5)× (3x-5)
$= (3 x)^{3} - 5^{3} - 3 (3 x) (5) (3 x - 5)$
It is in the form of $a^{3} - b^{3} - 3 a b (a - b) = a^{3} - b^{3}$
So, $(3 x)^{3} - 5^{3} - 3 (3 x) (5) (3 x - 5) = (3 x - 5)^{3}$
Therefore, the factors of the given expression is $(3 x - 5)^{3}$ .

Suggest Corrections

Similar questions

The expanded form of $(3 x - 5)^{3}$ is
(a) $27 x^{3} + 135 x^{2} + 225 x - 125$
(b) $27 x^{3} + 135 x^{2} - 225 x - 125$
(c) $27 x^{3} - 135 x^{2} + 225 x - 125$
(d) none of these

Use the appropriate article:

I've got _____ problem. Can you help me?

Q. can u give some factorization using indentities problems

Q. Factorise

27 x^{3} + y^{3} + z^{3} - 9 x y z

using identity

Change the sentence in indirect speech:

"Can you solve this problem?" he asked me.

Join BYJU'S Learning Program

Factorize using Identity 27x3-135x2-225x-125.

Given expression: 27x³-135x²-225x-125=(3x)³ + (-5)³ - 3(3x)×(5)× (3x-5)=(3x)3−53−3(3x)(5)(3x−5)It is in the form of a3−b3−3ab(a−b)=a3−b3So, (3x)3−53−3(3x)(5)(3x−5)=(3x−5)3Therefore, the factors of the given expression is (3x−5)3.

Factorize using Identity 27x³-135x²-225x-125.