Factorize:

$(x + 1)^{2} - (y - 1)^{2}$

$[x - y + 2] [x + y]$

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

$[x + y - 2] [x - y]$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

$[x - y + 2] [x - y]$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

$[x - y - 2] [x - y]$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A
$[x - y + 2] [x + y]$

$(x + 1)^{2} - (y - 1)^{2}$

$[(x + 1) - (y - 1)] [(x + 1) + (y - 1)]$

$[x + 1 - y + 1] [x + 1 + y - 1]$

$[x - y + 2] [x + y]$

Suggest Corrections

Similar questions

Factorize:

$(x + 2) (x^{2} + 25) - 10 x^{2} - 20 x$

\begin{matrix} X = sin (θ + \frac{7 π}{12}) + sin (θ - \frac{π}{12}) + sin (θ + \frac{3 π}{12}), Y = cos (θ - \frac{7 π}{12}) + cos (θ - \frac{π}{12}) + cos (θ + \frac{3 π}{12}) p r o v e t h a t \frac{x}{y} - \frac{y}{x} = 2 tan 2 θ . \end{matrix}

Reduce the expression $y = \frac{x^{2} - x + 1}{x^{2} + x + 1}$ to the form $a x^{2} + b x + c$ and give condition for x to be real.

Join BYJU'S Learning Program