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Question
Factorize : x2−1−2a−a2.
Factorize : x2−1−2a−a2.
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Solution
=x2−(1+2a+a2)=(x)2−(1+a)2{∵a2−b2=(a+b)(a−b)}=(x+1+a)(x−1−a)=(x+a+1)(x−a−1)
=x2−(1+2a+a2)=(x)2−(1+a)2{∵a2−b2=(a+b)(a−b)}=(x+1+a)(x−1−a)=(x+a+1)(x−a−1)
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