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Question

Factorize : x2−3ax−88a2

A
(2x11a)(x2+8a)
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B
(2x11a)(2x28a)
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C
(x11a)(x+8a)
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D
(xa)(x+8a)
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Solution

The correct option is C (x11a)(x+8a)
x23ax88a2
=x211ax+8ax88a2
=x(x11a)+8a(x11a)
=(x11a)(x+8a)

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