Factorize $x^{2} + 7 x + 10$

(x + 2) (x + 5)

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

(x - 2) (x + 5)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

(x - 2) (x - 5)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

(x + 2) (x - 5)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $(x + 2) (x + 5)$
Given equation is $x^{2} + 7 x + 10$
$= x^{2} + 5 x + 2 x + 10$
$= x (x + 5) + 2 (x + 5)$
$= (x + 2) (x + 5)$
Thus, $x^{2} + 7 x + 10 = (x + 2) (x + 5)$
Hence, option A is correct.

Suggest Corrections

Similar questions

Factorize $2 x^{2} - 7 x + 5 = 0$

\int \sqrt{x^{2} + 2 x + 5} dx is equal to

\frac{x^{2} - 7 x + 10}{x^{2} - 5 x - 14} \times \frac{x^{3} + 8}{x^{3} - 8} \times \frac{x^{2} + 2 x + 4}{x^{2} - 2 x + 4} \times \frac{x - 7}{x - 5} = ?

Which of the following are the factors of $36 x^{2} - 49 y^{2}$ ?

\int \sqrt{(x^{2} + 2 x + 5)} d x

Join BYJU'S Learning Program