Factorize: $x^{2} - 7 x + 12 = 0$

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Solution

$x^{2} - 7 x + 12 = 0$
$x^{2} - 4 x - 3 x + 12 = 0$ [using mid term expansion]
$x (x - 4) - 3 (x - 4) = 0$
$(x - 3) (x - 4) = 0$
$x - 3 = 0 o r x - 4 = 0$
$[x = 3]$ or $[x = 4]$

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x^{2} + 7 x + 12 = 0

x^{2} + 7 x + 12 = 0

x^{2} + 7 x + 12

Factorize: $x^{2} - 7 x + 12$ .

x^{2} + 7 x + 12

x^{2} - 7 x + 12 = 0

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