Factorize- x-2-7x-12-x-3-x-4-x-3-x-4-x-3-x-4-x-3-x-4-

The correct option is A (x 3)(x 4)We have to break up 7x in the nbsp;given expression into two parts in such a way that their sum is 7x and the product of th ...

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Standard VIII

Mathematics

Factorize: x^...

Question

Factorize: $x^{2} - 7 x + 12$ .

(x - 3) (x - 4)

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(x + 3) (x - 4)

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(x - 3) (x + 4)

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(x + 3) (x + 4)

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Solution

The correct option is A $(x - 3) (x - 4)$
We have to break up $7 x$ in the given expression into two parts in such a way that their sum is $7 x$ and the product of their coefficients is $12$ .
$x^{2} - 7 x + 12$
$= x^{2} - 4 x - 3 x + 12$
$= x (x - 4) - 3 (x - 4)$
$= (x - 3) (x - 4)$

Thus, $x^{2} - 7 x + 12$ can be factorised as $(x - 3) (x - 4)$ .

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Similar questions

${lim}_{x \to - 2} \frac{x^{3} + x^{2} + 4 x + 12}{x^{2} - 3 x + 2}$

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$12 x - 3 x + 4 x - 3 x - 7 x$ equals ___ .

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Standard VIII Mathematics

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Factorize: x2−7x+12.

The correct option is A (x−3)(x−4)We have to break up 7x in the given expression into two parts in such a way that their sum is 7x and the product of their coefficients is 12. x2−7x+12 =x2−4x−3x+12 =x(x−4)−3(x−4) =(x−3)(x−4) Thus, x2−7x+12 can be factorised as (x−3)(x−4).

Factorize: $x^{2} - 7 x + 12$ .