Question

Factorize : $x^2-7x+12$

• A. 0
• B. (x+3)(x-4)
• C. (x-3)(x+4)
• D. (x+3)(x+4)

Answer 1

The correct option is A

0

We have to break up $7x$ in the given expression into two parts in such a way that their sum is $7x$ the product of their coefficients is $12$
$x^2-7x+12$
$=x^2-4x-3x+12$
$=x(x-4)-3(x-4)$
$=(x-3)(x-4)$

Thus, we can see that $(x-3)$ and $(x-4)$ are the two factors of $x^2-7x+12$