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Byju's Answer
Standard VIII
Mathematics
Factorisation by Regrouping Terms
Factorize: x...
Question
Factorize:
x
2
+
a
x
−
(
6
a
2
−
5
a
b
+
b
2
)
.
Open in App
Solution
Now,
x
2
+
a
x
−
(
6
a
2
−
5
a
b
+
b
2
)
=
x
2
+
a
x
−
(
6
a
2
−
3
a
b
−
2
a
b
+
b
2
)
=
x
2
+
a
x
−
(
3
a
−
b
)
(
2
a
−
b
)
=
x
2
+
{
(
3
a
−
b
)
−
(
2
a
−
b
)
}
x
−
(
3
a
−
b
)
(
2
a
−
b
)
=
x
(
x
+
3
a
−
b
)
−
(
2
a
−
b
)
(
x
+
3
a
−
b
)
=
(
x
+
3
a
−
b
)
(
x
−
2
a
+
b
)
Suggest Corrections
0
Similar questions
Q.
Product of
6
a
2
−
7
b
+
5
a
b
and
2
a
b
is
Q.
Question 12
Product of
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−
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+
5
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b
and
2
a
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is
a)
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a
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c)
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d)
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Q.
Add the following algebraic expressions using vertical method
(i)
4
a
2
+
5
b
2
+
6
a
b
;
3
a
b
;
6
a
2
−
2
b
2
;
4
b
2
−
5
a
b
Q.
Which of the following identity can be used to factorize
x
2
−
4
y
2
?
Q.
Simplify:
(
−
10
a
3
b
+
12
a
2
b
2
−
6
a
b
3
)
−
(
8
a
3
b
+
6
a
2
b
2
−
9
a
b
3
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