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Question

Factorize:
x3+y3+z3=3xyz.

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Solution


x3+y3+z33xyz=0
x3+y3+3x2y+3xy2+z33xyz3x2y3xy2=0
(x+y)3+z33xy(x+y+z)=0
(x+y+z)((x+y)2+z2(x+y)z)3xy(x+y+z)=0
(x+y+z)(x2+2xy+y2+z2xyxz3xy)=0
(x+y+z)(x2+y2+z2xyyzzx)=0.

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