Simplifying y2−10y+25.
y2−10y+25
=y2−5y−5y+25
=y(y−5)−5(y−5)
=(y−5)(y−5)
A circle of radius ‘5’ touches the coordinate axes in the first quadrant. If the circle makes one complete roll on x-axis along the positive direction, then its equation in new position is
The equation of the circle which passes through the points (2, 3) and (4, 5) and the centre lies on the straight line y – 4x + 3 = 0, is