Factorize : $z^{2} + 4 z - 12$

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Solution

$z^{2} + 4 z - 12$

$= z^{2} + 6 z - 2 z - 12$

$= z (z + 6) - 2 (z + 6)$

$= (z - 2) (z + 6)$

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\int \frac{{3 z}^{3} - 8 z + 5}{\sqrt{z^{2} - 4 z - 7}} d z = (z^{2} + a z + 36) \sqrt{z^{2} - 4 z - 7} + b ℓ n | z - 2 + \sqrt{z^{2} - 4 z - 7} | + C

a, b ϵ I

C

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