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Question
Factorize: z2−32z−105
Factorize: z2−32z−105
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Solution
We have: z2−32z−105
We have to split (−32) into two numbers such that their sum is (−32) and their product is (−105).
Clearly, −35+3=−32 and −35×3=−105
∴z2−32z−105
=z2−35z+3z−105
=z(z−35)+3(z−35)
=(z−35)(z+3)
We have: z2−32z−105
We have to split (−32) into two numbers such that their sum is (−32) and their product is (−105).
Clearly, −35+3=−32 and −35×3=−105
∴z2−32z−105
=z2−35z+3z−105
=z(z−35)+3(z−35)
=(z−35)(z+3)
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