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Question

Factors of 49p236 is/are:


A

(7p6)

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B

(7p+6)

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C

(7p+6)(7p+6)

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D

(6p+7)

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Solution

The correct options are
A

(7p6)


B

(7p+6)


Factorise using identities (a)2(b2)=(a+b)(ab):

49p236 can be written as (7p)2(6)2=(7p6)(7p+6)

This cannot be factorised into any further factors.


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