Factors of $63 a^{2} - 112 b^{2}$ are

7

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(3 a - 4 b)

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(3 b + 4 a)

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(3 a + 4 b)

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Solution

The correct options are
A $7$
C $(3 a + 4 b)$
D $(3 a - 4 b)$
$63 a^{2} - 112 b^{2}$
$= 7 (9 a^{2} - 16 b^{2})$
$= 7 [(3 a)^{2} - (4 b)^{2}]$
$= 7 (3 a + 4 b) (3 a - 4 b)$

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