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Factorisation by Common Factors

Factors of 6x...

Question

Factors of $6 x^{2} - 19 x - 20$ are

$(- x + 4) (- 6 x + 5)$

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$(x + 4) (6 x + 5)$

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$(x - 4) (6 x + 5)$

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$(- x - 4) (6 x + 5)$

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Solution

The correct option is C
$(x - 4) (6 x + 5)$

$6 x^{2} - 19 x - 20$

$6 x^{2} - 24 x + 5 x - 20$

$6 x (x - 4) + 5 (x - 4)$

$(x - 4) (6 x + 5)$

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Similar questions

Δ (x) = ∣ ∣ ∣ ∣ ∣ \begin{matrix} x^{2} - 5 x + 3 & 2 x - 5 & 3 3 x^{2} + x + 4 & 6 x + 1 & 9 7 x^{2} - 6 x + 9 & 14 x - 6 & 21 \end{matrix} ∣ ∣ ∣ ∣ ∣ = a x^{3} + b x^{2} + c x + d

(4 x^{4} - 5 x^{3} - 39 x^{2} - 46 x - 2)

(x^{2} - 3 x - 5)

(- 5 x + 8)

- 1

x^{4} + a x^{3} - 19 x^{2} - 46 x + 20

a

81^{3 x - 5} = 243^{7 x - 9}

46 x - \frac{x}{50}

x (6 x - 5 y) - 4 (6 x - 5 y)^{2}

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