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Factorisation by Common Factors

Factors of ...

Question

Factors of $8 x^{2} - 18 x + 9$ are :

(4 x - 3)

and

(2 x + 3)

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(8 x - 1)

and

(x - 9)

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(8 x - 3)

and

(x - 3)

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(2 x - 3)

and

(4 x - 3)

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Solution

The correct option is C $(2 x - 3)$ and $(4 x - 3)$
$8 x^{2} - 18 x + 9 = 8 x^{2} - 12 x - 6 x + 9 = 4 x (2 x - 3) - 3 (2 x - 3) = (2 x - 3) (4 x - 3)$

Suggest Corrections

Similar questions

4 x^{2} + 8 x + 3

(x + 1) (x + 3)

(2 x + 1) (2 x + 3)

(2 x + 2) (2 x + 5)

(2 x - 1) (2 x - 3)

Without actual division ,proovd that 2x^4-8x^3+3x^2+12x-9 is actually divisible by x^2-4x+3?

f (x) = \frac{x^{3} + 2 x^{2} - 9}{2 x^{3} - 8 x + 3}

x^{2} - [2 x - 8 x - 4] = \frac{4 x - 27}{3} - 3

Subtract:

(1) $4 x^{2}$ and $- 6 x y^{2}$

(2) $6 x^{3}$ and $- 2 x^{3}$

(3) $9 x y a n d 5 x y$

(4) $- 7 x^{3}$ and $- 8 x^{3} y$

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